Jawab:
[tex]\int\limits^1_0 {3x^{2} } \, dx[/tex]
[tex]=3\times\frac{1}{2+1} x^{2+1}[/tex]
[tex]=3\times\frac{1}{3} x^{3}[/tex]
[tex]=x^{3}[/tex]
= 1³ - 0³
= 1
[tex]\int\limits^2_1 {x^{2} +2x} \, dx[/tex]
[tex]=\frac{1}{2+1} x^{2+1} +2\times\frac{1}{1+1} x^{1+1}[/tex]
[tex]=\frac{1}{3} x^{3} +2\times\frac{1}{2} x^{2}[/tex]
[tex]=\frac{1}{3} x^{3} +x^{2}[/tex]
[tex]=(\frac{1}{3} (2)^3+2^{2} )-(\frac{1}{3} (1)^3+1^{2} )[/tex]
[tex]=5\frac{1}{3}[/tex]
[tex]\int\limits^1_0 {x(2x^{2}+3) } \, dx[/tex] (cara paling mudah utk integral, ubah perkalian ke penjumlahan)
[tex]=\int\limits^1_0 {2x^3+3x} \, dx[/tex]
[tex]=2\times\frac{1}{3+1} x^{3+1} +3\times\frac{1}{1+1} x^{1+1}[/tex]
[tex]=\frac{1}{2} x^{4} +\frac{3}{2} x^{2}[/tex]
[tex]=(\frac{1}{2} (1)^{4} +\frac{3}{2} (1)^{2})-(\frac{1}{2} (0)^{4} +\frac{3}{2} (0)^{2})[/tex]
= 2
[tex]\int{(x+2)(x-1)} \, dx[/tex]
[tex]=\int {x^{2} +x-2} \, dx[/tex]
[tex]=\frac{1}{2+1} x^{2+1} +\frac{1}{1+1} x^{1+1} -2x[/tex]
[tex]=\frac{1}{3} x^{3} +\frac{1}{2} x^{2} -2x[/tex]
[tex]=(\frac{1}{3}(1)^{3} +\frac{1}{2} (1)^{2} -2(1))-(\frac{1}{3} (-1)^{3} +\frac{1}{2} (-1)^{2} -2(-1))[/tex]
[tex]=-3\frac{1}{3}[/tex]
[answer.2.content]
